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Messages - suppusmac

Pages: [1] 2 3 ... 8
1
Other / Re: Corrupt-a-wish, the forum game
« on: 10 Mar 2013, 16:15:28 »
Wish granted, but you're now very clumsy and break your stuff instead.

I wish I was a robot.

2
Other / Re: A simple, silly riddle.
« on: 10 Mar 2013, 16:14:09 »
Warm switches, connectins that fizzle...can we say bad wiring? :O
The real answer involves the lightbulb getting hotter. So, I am assuming the wiring is fine.

3
Other / Re: Since riddles seem to be popular lately...
« on: 9 Mar 2013, 19:25:08 »
This one is old.
You look through the mirror you saw what you saw, you saw a saw, you saw the table is half, two halves make a "hole", that hole is your exit.

4
Other / Re: My VERY simple and silly riddles
« on: 8 Mar 2013, 22:59:51 »
2.
The first password is "altered"
The second/new password is "distinct"
1. I have the answer, but I'd rather this post be more than person attempting the riddle. So, have fun with number 1 guys :P

5
Other / Re: A simple, silly riddle.
« on: 8 Mar 2013, 22:56:03 »
Set switch #1 to the on position and switches #2 and #3 to the off position.
Wait ten minutes.
Turn switch #1 off and switch #2 on.
Enter the room and examine the bulb. If the bulb is on, then it’s controlled by switch #2. If the bulb is off and warm or hot, then it’s controlled by switch #1 (because it was recently left on for ten minutes which caused it heat up). If the bulb is off and room temperature, then, by process of elimination, it must be controlled by switch #3.

Or you could listen to the connection fizzle

  8|

Correct!

Just don't close the door when you go in and out of the room? lol
I said you cannot leave the door open *Mad face*.

6
Other / Another Simple, Silly Riddle
« on: 8 Mar 2013, 02:21:23 »
I actually made this one up, so there may be a flaw in it.

Suppose you are playing a game of cards with someone, using a standard deck of 52 cards.
He asks you to pick a card from the deck, place it down on the table so that you can not see it. (You never saw it)
Now he takes away about half of the remaining cards. Leaving 26 (Discarding 25).
He asks you to again, pick a card and place it on the table so that you can not see it. (Once again, you never saw the card)
Now he discards all the cards but one, puts it face down on the table, this is his card. Neither of you know what any of the three cards are.
So now he has 1 card face down, and you have 2 cards face down.
He searches through the pile and notices there is no ace of spades in the pile of discarded cards.
He bets you 50$ (or whatever currency you use) that his card is the ace of spades, and if one of your two cards is the ace of spades, then you get the 50$.
Do you take this bet? (do you have the advantage or does he have the advantage, or is it equal?)
Explain your answer.

7
Other / Re: Thoughts on Piracy (Cracking)
« on: 8 Mar 2013, 02:00:10 »
Opportunity over risk. It's a decision people make for themselves. It is technically illegal but there are some other stupid things that are illegal.

8
Other / Re: Math and Stuff!
« on: 8 Mar 2013, 01:58:22 »
C=2*pi*r
Rearranging: r = C / (2*pi)
If r and C have the same units, then add 6 to C and rearrange:
r = (C+6) / (2*pi) = C/(2*pi) + 6/(2*pi)
The radius increases by 6/(2*pi) using any unit, for any circle of radius r. If we said pi is about 3, then 2*pi is 6, the radius increases by about 1.
Three things,
1. Sorry for not making my explanation as simple as yours, and
2. I showed my brother this problem after you posted it, and he got mad because he thought there was no way it was 1 meter. So he took my calculator and divided by (10^pi) twice, and claimed that was the real answer, so he wouldn't look stupid in front of my parents...
3. Since doing this problem I memorize the circumference and radius of the earth :P

9
Other / Re: A challenge for anyone good at math
« on: 8 Mar 2013, 01:53:01 »
I was not sure on exactly what the problem was asking, but If I realized that the altitude I could have made when I was explaining the second part of my problem was actually the same as the radius I would have got it. Doh. However, I got the max distance were you could see the very bottom of the tower if looking from tower to tower. So that's something.

10
Other / Re: A simple, silly riddle.
« on: 8 Mar 2013, 01:47:21 »
No one has correctly answered the riddle yet. But I feel like not everyone understand exactly what the question is.

You need to flick the switches when you're outside of the room, so you can do that before or after you enter (or before and after), but you can only enter the room once.
So a little hint, based on what you infer when you go in the room will help you find your ultimate solution.
Finally your job is to create a method that allows you to always determine which light switch powers on the lightbulb.
Your job is not to just guess which one powers it on, as that will only work 1/3 of the time.
Hopefully that will help anyone who was confused.

11
Other / Re: A simple, silly riddle.
« on: 7 Mar 2013, 01:32:57 »
Ok, assuming light bulbs work in this make believe situation like they do in real life I know 3 things.

1.  When the right switch is hit the bulb turns on.  2.  When a light is on, it gets hot.  3.  When it doesn't go on it stays room temperature or cool.  Therefore, just like before, three equations and three unknowns.  This riddle is solvable.

Based upon this, I don't think I need to go any further, as i understand what I need to do.  I'll leave the sequencing procedure for the switches to another person to chime in on.

That's my two cents!

:D

Max
If you've never seen the riddle, good job!
If you have, good job for not spoiling it for someone else, but giving a hint!

12
Other / Re: A challenge for anyone good at math
« on: 7 Mar 2013, 01:31:20 »
I'm not sure but I think you'd solve it like this:
The person's line of sight it tangent to a circle... So that tangent line will be what we are trying to find, well at least until it "touches" earth.
The point from the center of the circle to the point the tangent "hits" the earth creates a right angle, That line segment is equal to the radius of the earth. Then you can make the next leg of the right triangle the radius to the person on the tower. I'm going to assume we're not calculating the height of the person into the equation as well.
So now we have one leg that is 6,380,000 meters (a) and the other that is 6,380,050 meters(c). So c squared - a squared = b squared, how far we can see! Do some calculations... And we find it's about 25,258.71137 meters, I'll round that to 25259 meters. So that's about 25 kilometers. But that would be the bottom of the tower...

So If we're not looking at the bottom the tower, rather the top, I'd be left with an isosceles triangle... Two measures of 6380,050 from the center to the height of the two towers and x, the distance between the tops of the two towers. Well, I know 0<x<12760100. Other than that I can't find that distance using anything I know. Even if I drop an altitude from the earth's center, I couldn't do much considering I'd be left with the radius, which I know, the altitude, which is unknown, and half of x, which is also unknown at that point. So I'll go with my first answer.

13
Other / Re: A simple, silly riddle.
« on: 6 Mar 2013, 18:41:43 »
In my diagram it didn't show it well, but the switches are actually on the outside of the room, you cannot flick any of the light switches once you are inside.

14
Other / Re: A challenge for anyone good at math
« on: 6 Mar 2013, 18:14:56 »
No, you and Fred are correct.  I went back and looked at the assumptions which i made.  You are absolutely right, there isn't enough information to solve.  Too bad, I love math too.  Nevertheless, even if an angle were given, it would have been too easy to solve.  We need something more challenging.

:D

Max
There was the earth and belt thingy challenge Fred posted, But I already answered it, you can try and just not read my answer if you want to do it on your own, but here is the question:
Imagine a belt snug around a spherical earth's equator so that there's no space between it and the earth, make the belt 6 inches longer, how far does the belt raise above the earth's equator?

15
Other / A simple, silly riddle.
« on: 6 Mar 2013, 18:09:56 »
Assume there is a room.
This room as no way of seeing in or out, but there is a door that can be opened. When the door is closed, theres no way of seeing into the room at all.
There are 3 light switches on the wall outside of the room. Again, outside of the room!
Inside of the room there is ONLY a light bulb, which one, and only one of the three switches turns it on.
Your job is to find out which one of these switches turns on the light bulb.

The rules are:
- You can alter/ flick on and off any of the light switches (or any combination) as much as you want BEFORE you go into the door.
- You can only go into the room once, you may not leave the door open, you can't punch through the door, nothing like that.
-There's nothing inside the room but a light bulb, and you cannot bring anything inside the room.
-You can't take apart the lightbulb. Don't be on of the crafty electricians!
-Again, There is ONLY a lightbulb in the room that turns on and off.

So, what is the guaranteed way to find out which switch turns on the light?

Bad pixel diagram:

0=switches X=Lightbulb  l/- = Walls (That you cannot see through)

-0-0-0--Door-----
----------         -----
l                        l
l           X           l
l                        l
--------------------

16
Other / Re: A challenge for anyone good at math
« on: 6 Mar 2013, 17:41:57 »
The only way to make two right triangles is bringing down an altitude from one of the angles.
Heres are all 6 of your right triangle possibilities.

From angle B (opposite of side b):
The side being "hit" with an altitude is 10.4, since it's an altitude you don't know how it's altered, and I believe it's also impossible that creates a midpoint, because the only triangle I know that creates a midpoint with its altitude is a 60-60-60 aka an equilateral triangle.
You'd get one triangle:
Sides: Altitude, Side c, and a portion of side b. All lengths unknown.
The other:
Sides: Altitude, Side a, a portion of of side b. A is known to be 7.8.

From angle A:
One triangle:
Sides: Altitude, side c, a portion of side a. All lengths unknown.
The other:
Side: Altitude, side b, a portion of side c. b is known to be 10.4

From angle C:
One triangle:
Sides: Altitude, a potion of unknown c, side a. A is known to be 7.8
The other:
Sides: Altitude, a potion of unknown c, side b. Side b is known to be 10.4

You only have a max of one side measurement and a right angle. The law of cosines or sines cannot help you with a 90 degree angle and one side length.




17
Other / Re: Math and Stuff!
« on: 6 Mar 2013, 17:21:49 »
The answer is about 1 meter.
40,075km is about the circumference of the world.
Multiply by 1000 to convert to meters, so 40,075,000 meters, Divide this by Pi to get about 12756268.6.
Add 6 the circumference.
40,075,006. Divide by Pi to get the diameter.
About 12756270.6.
The diameter is increased by about 2. However, we need the radius to find how much it's stretched out in ANY direction. The radius is half the diameter, half both of those numbers to find that it is 1 meter. (Which is also half of 2, so you can do it that way if you want).
Tada, math!

I'm a bit lazy, so I'm won't show the numbers after you divide them by 2, so here's an easy example: 4-2 = 2. Okay.
4/2 =2
2/2 =1
2-1 =1
Same principle applies with all numbers, including the two I was working with above.


18
Other / Re: A challenge for anyone good at math
« on: 6 Mar 2013, 17:20:31 »
You are not given any angles. How do you know what degree to bisect the angle at? You don't know how bringing an altitude down will effect the angles, not only that, since you aren't given any angles, now you have two right triangles with one measurement each. OR you could bring an altitude down from A and have 7.8 under it,(or the same from b, with 10.4) but since the altitude can be anywhere on that leg, you don't know how to cut up 7.8, it could be half, or maybe not. But you don't have any angles so you can't possibly use the law of sines or cosines to find the measure of a side or angle to help you out from one of those right triangles you made.
Could you please show me your work to find the the measurements of this triangle?

19
What's the time limit? Because I have high hopes in my town design, but it won't be done for a while, a month at minimum...

20
Server Announcements / Re: Noobstown's 2nd Birthday Bash!
« on: 6 Mar 2013, 16:56:19 »
This should be fun.

21
Other / Re: A challenge for anyone good at math
« on: 6 Mar 2013, 16:51:12 »
You do have the wrong triangle (we know by the values given we have a scalene triangle).  It is not necessary to know, or to have a right triangle as part of the given information. It makes solving a bit more complicated, but not by much.  It is possible to solve for C.  Even if you only know for every right triangle A squared plus B squared = C squared you can still solve with two equations and two unknowns.

After calculating, the height of the given triangle H = 6.24

:D

Max

It can be a right triangle, with the length of the hypotenuse being 13, assuming side a and b are the lengths of the legs... I really don't know what they're supposed to be (angle measurements?). And the values of the third leg of the triangle can be shown like so: 18.2>c>2.6.  And If it's not a right triangle, you'd need at least one angle value as well to use the law of sines or the law of cosines to find the rest of the measurements. If it is a right triangle, and c is the hypotnuse, then you already have the height and base of the triangle, which means you can find the area, and c is only necessary for finding the circumference.

If this was a right triangle here's the solution as far as I can go:
c=13
So we can find D to be 135.2 (So the diameter was 43.03549661...? Seems odd, but I'll keep going)
The area doesn't require c since c is the hypotenuse, b*a*1/2 = 40.56
The base of the rectangular prism is 175.76 square units.
Multiply that by 5.
878.8 cubic unites
But I completely assumed half of the problem.
If that triangle is not a right triangle I'd need another angle to find out the rest of the measurements, from that I could make a right triangle within that triangle to help me find the height of the triangle. Otherwise, to my knowledge, you cannot find the area of that triangle.

22
Other / Re: Linked Words Game
« on: 5 Mar 2013, 02:20:09 »
Exam answers

23
Other / Re: Corrupt-a-wish, the forum game
« on: 5 Mar 2013, 02:19:36 »
Wish granted, you have it for 1 second.

I wish I could draw perfect circles.

24
Towns & Nations / Re: World Map
« on: 3 Mar 2013, 19:16:22 »
ShinSekai does mean "New World" but i chose it because in the popular Anime called "One Piece" they have 2 seas 1 the "Grandline" and the second "ShinSekai/New World" so eventually i got the name from an Anime and what am i talking about ? ihafdusajhd bla!
It's a whole new world,
A new fantastic point of view...

25
Music / Re: I'm so ashamed in myself.
« on: 3 Mar 2013, 13:23:42 »
You can always get an equally catchy song stuck in your head.

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